4÷2+√3+√7=√a+√b+√c find a b c
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4÷2=2=√4
Therefore√4+√3+√7=√a+√b+√c
By this we can know that,
A=4
B=3
C=7
So,abc=4×3×7
=84
Therefore√4+√3+√7=√a+√b+√c
By this we can know that,
A=4
B=3
C=7
So,abc=4×3×7
=84
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