Question

4
2) A car initially at rest attains a velocity of 72km/hr over a
distance of 25 meteres. Find its acceleration and the time
in which it picks up the above velocity.​

Answer 1

Answer:

1.25 second is the ans.

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Answer 2

Answer:

We will make use of the kinematic equations of motion here.

u = 0

v = 72 km/h = 20 m/s

s = 25 m

Using the third equation of motion, we can say:

v² = u² + 2as

400 = 0 + 2 × a × 25

50a = 400

a = 8 m/s²

Using the second equation of motion, we can say:

$s = ut + \frac{1}{2}at^{2}$

25 = 0 × t + $\frac{1}{2}$ × 8 × t²

25 = 4t²

t² = 25/4

t = 5/2

t = 2.5 sec

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