Question

4 2 (ii) H S (aq) + Cl2 (8) —→ S (s) + CI+ (aq)
by ion electron method??
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Answer 1

Answer:

3N2​H4​(l)+4ClO3−​(aq)→6NO(g)+4Cl−(aq)+6H2​O(l)

Explanation:

Total decrease in oxidation number of N is 8. Total increase in the oxidation number of Cl is 6.

Multiply N2​H4​ with 3 and multiply ClO3−​ with 4.

3N2​H4​(l)+4ClO3−​(aq)→NO(g)+Cl−(aq)

Balance N and Cl atoms.

3N2​H4​(l)+4ClO3−​(aq)→6NO(g)+4Cl−(aq)

Balance the O atoms are by adding 6 water molecules.

3N2​H4​(l)+4ClO3−​(aq)→6NO(g)+4Cl−(aq)+6H2​O(l)

This is the balanced chemical equation.