Math, asked by harshvardhanH, 11 months ago

4^2/x-5*4^1/x+4=0 then the value

Answers

Answered by pal69
2
4^1/x-5.4^1/x+4=0

let,4^1/x=y,then

=>. y² -5y+4=0

=>. y²-4y-y+4=0

=.> (y-4)(y-1)=0

=> y=4

=>. 4^1/x=4

=>4^(1/x)-1=4^0

=>1/x. -1= 0

=. x=1,

let,y=1

=.>. 4^1/x=1,

=>4^1/x=4^0

=>1/x=0,

x=infinite and=1
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