4^2/x-5*4^1/x+4=0 then the value
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4^1/x-5.4^1/x+4=0
let,4^1/x=y,then
=>. y² -5y+4=0
=>. y²-4y-y+4=0
=.> (y-4)(y-1)=0
=> y=4
=>. 4^1/x=4
=>4^(1/x)-1=4^0
=>1/x. -1= 0
=. x=1,
let,y=1
=.>. 4^1/x=1,
=>4^1/x=4^0
=>1/x=0,
x=infinite and=1
let,4^1/x=y,then
=>. y² -5y+4=0
=>. y²-4y-y+4=0
=.> (y-4)(y-1)=0
=> y=4
=>. 4^1/x=4
=>4^(1/x)-1=4^0
=>1/x. -1= 0
=. x=1,
let,y=1
=.>. 4^1/x=1,
=>4^1/x=4^0
=>1/x=0,
x=infinite and=1
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