Question

4^20+1 is divisible by m then which
the following is always divisible by m

(as 4^40 + 1
(6) 4^60 + 1
(c) 4^10 + 1
(d) non of these​

Answer 1

answer : option (D) none of these.

apply application :

• aⁿ + bⁿ is divisible by (a + b) only when n is an odd number.
• aⁿ + bⁿ is not divisible by (a + b) when n is an even number.

given, 40^20 + 1 is divisible by m.

or, 40^20 + 1^20 is divisible by m.

can you assume, a = 40 , b = 1 and n = 20

now 40^20+ 1^20 is in the form of aⁿ + bⁿ where n is even number (i.e., 20)

so, 40^20 + 1^20 can't be divisible 40 + 1 / 40^5 + 1^5/ 4^10 + 1^10.

so the correct option is option (D) none of these.

also read similar questions:prove that n²-n is divisible by two for every positive integer n.

https://brainly.in/question/3135597

for any positive integer 'n' ,prove that (n³ -n) is divisible by 6 .

https://brainly.in/question/1328990

Answer 2

Answer:

G

Step-by-step explanation: