A sector of radius of 12cm has the angle of 60° then find the major segment and minor segment
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Area of Minor arc=x°/360°πr²
=60°/360°×22/7×12×12
=1/6×22/7×12×12
=75.4cm² is the area of minor arc
Area of major arc=300/360×22/7×12×12
=30/36×22/7×12×12
=2640/7
=377.1 cm² is the area of major arc
=60°/360°×22/7×12×12
=1/6×22/7×12×12
=75.4cm² is the area of minor arc
Area of major arc=300/360×22/7×12×12
=30/36×22/7×12×12
=2640/7
=377.1 cm² is the area of major arc
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Answer:
Step-by-step explanation:
Area of Minor arc=x°/360°πr²
=60°/360°×22/7×12×12
=1/6×22/7×12×12
=75.4cm² is the area of minor arc
Area of major arc=300/360×22/7×12×12
=30/36×22/7×12×12
=2640/7
=377.1 cm² is the area of major arc
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