Question

A sector of radius of 12cm has the angle of 60° then find the major segment and minor segment

Answer 1

Area of Minor arc=x°/360°πr²
=60°/360°×22/7×12×12
=1/6×22/7×12×12
=75.4cm² is the area of minor arc

Area of major arc=300/360×22/7×12×12
=30/36×22/7×12×12
=2640/7
=377.1 cm² is the area of major arc

Answer 2

Answer:

Step-by-step explanation:

Area of Minor arc=x°/360°πr²

=60°/360°×22/7×12×12

=1/6×22/7×12×12

=75.4cm² is the area of minor arc

Area of major arc=300/360×22/7×12×12

=30/36×22/7×12×12

=2640/7

=377.1 cm² is the area of major arc