4(2a-3)² - 3(2a-3)(a-1) - 7(a-1)²
Factorise:
Georges2467:
hi simriddhi
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Answered by
130
hey mate!
the correct answer is = Let (2a - 3) be x and (a - 1) be y.
4(2a - 3)^2 - 3(2a - 3)(a - 1) - 7(a - 1)^2
= 4x^2 - 3xy - 7y^2
= 4x^2 - 7xy + 4xy - 7y^2
= (4x^2 - 7xy) + (4xy - 7y^2)
= x(4x - 7y) + y(4x - 7y)
= (x + y)(4x - 7y)
= ((2a - 3) + (a - 1))(4(2a - 3) - 7(a - 1))
= (2a - 3 + a - 1)(8a - 12 - 7a + 7)
= (3a - 4)(a - 5)
Answered by
27
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