Question

4(2y-3) + 5(3y-4) = 14 how to solve this linear equation

Answer 1

$\large{HELLO FREIND}$

4(2y-3) + 5(3y-4) = 14
8y-12+15y-20=14
23y-32=14
23y=14+32
23y=46

y = 2

Answer 2

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Here is u r Ans ➡

✨
$= 4(2y - 3) + 5(3y - 4) = 14$
$= 8y - 12 + 15y - 20 = 14$

$= 23y - 32 = 14$

$= 23y = 14 + 32$
$= 23y = 46$

$y = 2$

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