Question

4(2z-3)+2(7z+1)+4=3(5z-1)+4 solve it

Answer 1

Answer:

z = 1

Step-by-step explanation:

4(2z - 3) + 2(7z + 1) + 4 = 3(5z - 1) + 4

8z - 12 + 2(7z + 1) + 4 = 3(5z - 1) + 4

8z - 12 + 14z + 2 + 4 = 15z - 3 + 4

22z - 6 = 15z + 1

22z - 15z = 1 + 6

7z = 7

z = 1

Answer 2

Answer:

4(2z-3)+2(7z+1)+4=3(5z-1)+4

8z-12+14z+2+4=15z-3+4

22z-6=15z+1

22z-15z=7

7z=7

z=1

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