Question

4√3÷2-√2-30÷4√3-3√2-3√2-3√2÷3+2√3

Answer 1

This is a question in the irrational numbers chapter.
I think the question given is this:

$\frac{4\sqrt3}{2-\sqrt2}-\frac{30}{4\sqrt3-3\sqrt2}-3\sqrt2-\frac{3\sqrt2}{3+2\sqrt3}\\\\Rationalizing\ denominators:\\\\\frac{4\sqrt3(2+\sqrt2)}{(2-\sqrt2)(2+\sqrt2)}-\frac{30(4\sqrt3+3\sqrt2)}{(4\sqrt3-3\sqrt2)(4\sqrt3+3\sqrt2)}-3\sqrt2-\frac{3\sqrt2(3-2\sqrt3)}{(3+2\sqrt3)(3-2\sqrt3)}\\\\\frac{8\sqrt3+4\sqrt6}{4-2}-\frac{120\sqrt3+90\sqrt2}{48-18}-3\sqrt2-\frac{9\sqrt2-6\sqrt6}{9-12}\\\\4\sqrt3+2\sqrt6-4\sqrt3-3\sqrt2-3\sqrt2+\frac{3}{2}\sqrt2-\sqrt6\\\\\sqrt6-\frac{9}{2}\sqrt2$

this is the answer to be given in this form.