Physics, asked by balamohan, 1 year ago

If 4^x-4^x-1=24 then [2*x]^x =


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Answered by TPS
0
4^x-4^{-x}=24\\ \\4^x- \frac{1}{4^x} =24\\ \\ let\ 4^x=t\\ \\t- \frac{1}{t}=24\\ \Rightarrow t^2-1=24t\\ \Rightarrow t^2-24t-1=0\\ \Rightarrow t=12+ \sqrt{145}\\ (t=12- \sqrt{145}\ is\ ignored\ as\ 4^x\ can't\ be\ negative )\\ \\thus\ 4^x=12+ \sqrt{145} \\2^x= \sqrt{4^x} = \sqrt{12+ \sqrt{145}}
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