Question

4√3+5√2/√48+√18=a+b√6


find the value of a and b. ​

Answer 1

Answer:

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Answer 2

Answer:

$\frac{9 + 4 \sqrt{6} }{15}$

Step-by-step explanation:

$\frac{4 \sqrt{3 } + 5 \sqrt{2} }{ \sqrt{48} + \sqrt{18} }$

$\sqrt{48} - \sqrt{18}$

$\frac{4 \sqrt{3} + 5 \sqrt{2} ( \sqrt{48} - \sqrt{18} ) }{ \sqrt{48} + \sqrt{18} ( \sqrt{48} - \sqrt{18} }$

$\frac{4 \sqrt{3} \sqrt{48} - 4 \sqrt{3} \sqrt{18} + 5 \sqrt{2} \sqrt{48} - 5 \sqrt{2} \sqrt{8} }{ \sqrt{48} \sqrt{48} - \sqrt{18} \sqrt{18} }$

$\frac{4 \times 4 \sqrt{3} \sqrt{3} - 4 \times 3 \sqrt{3} \sqrt{2} + 5 \times 4 \sqrt{2} \sqrt{3} - 5 \times 3 \times 2}{48 - 18}$

$\frac{4 \times 4 \times 3 - 4 \times 3 \sqrt{6} + 5 \times 4 \sqrt{6} - 5 \times 3 \times 2}{30}$

$\frac{48 - 12 \sqrt{6} + 20 \sqrt{6} - 30}{30}$

$\frac{18 + 8 \sqrt{6} }{30}$

$\frac{9 + 4 \sqrt{6} }{15}$

Hope it helps you