A shop sells erasers at $1 each and in packets of 6 and 1 packet for $4. Edmund wants to buy 38 erasers. What is the least amount of money that Edmund will need?
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The least amount of money that Edmund will need is $26.
Given, the cost of 1 rubber is $1
And, the cost of rubbers in packet is of $4 for 6 rubbers.
So, it is wise to buy rubbers in packets if the want more than 4 rubbers.
The maximum number of packets we can buy for 38 rubbers = 38/6 ≈ 6 packets.
So, the cost of 6 packets = 6×($4) = $24
No. of loose rubbers = 38-36 = 2
Cost of these 2 single rubbers = 2×($1) = $2
Thus, minimum cost is = $(24+2) = $26
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