Math, asked by narendrajoshi6400, 1 year ago

4. If Sin-cos =0 then the value of (sin4+cos4) is

Answers

Answered by sandy1816
15

Step-by-step explanation:

sinA-cosA=0

(sinA-cosA)²=0

1-2sinAcosA=0

sinAcosA=1/2

sin⁴A+cos⁴A

=(sin²A+cos²A)²-2sin²Acos²A

=1-2(1/4)

=1-1/2

=1/2

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