4√3+5√2/√48+√18 RATIONALISE THE DENOMINATOR
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4√3 + 5√2 / √48+√18
take the LCM of √48 and √18 and take the square out
=4√3 + 5√2 / 4√3 + 3√2
=4√3 + 5√2 X 4√3 - 3√2 / 4√3 + 3√2 x 4√3 - 3√2
=16 x 3 - 15 x 2 / 16 x 3 - 9 x 2
=48 - 30 / 48 - 18
=18 / 30
=3 / 5
take the LCM of √48 and √18 and take the square out
=4√3 + 5√2 / 4√3 + 3√2
=4√3 + 5√2 X 4√3 - 3√2 / 4√3 + 3√2 x 4√3 - 3√2
=16 x 3 - 15 x 2 / 16 x 3 - 9 x 2
=48 - 30 / 48 - 18
=18 / 30
=3 / 5
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Answered by
164
by rationalising the value we get the answer
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if you like my answer plz mark me as brainliest
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