Question

4,3,5=40 5,4,3=92,6,2,3=?​

Answer 1

The missing number(?) is "209".

Step-by-step explanation:

The given options are:

a. 92 b. 53 c. 47 d. 57

We have,

4, 3, 5 = 40 5, 4, 3 = 92

To find 6, 2, 3 = ?​

The pattern follow,

$a, b, c = a^{3} -(b^{2} +c^{2} )+10$,$a, b, c = a^{3} -(b^{2} +c^{2} )-8$, $a, b, c = a^{3} -(b^{2} +c^{2} )+6$.

$4, 3, 5 = 4^{3} -(3^{2} +5^{2} )+10=64-34+10=40$

$5, 4, 3 = 5^{3} -(4^{2} +3^{2} )-8=125-25-8=92$

Similarly,

$6, 2, 3 = 6^{3} -(2^{2} +3^{2} )+6=216-13+6=209$ = ?

∴ Missing number(?) = 209

Hence, the missing number(?) is "209".

Answer 2

53 is Correct option 4,3,5=40 5,4,3=92,6,2,3=?​

Step-by-step explanation:

options are

a) 92 b) 53 c) 47 d) 57

4,3,5 = 40

5,4,3 = 92

6,2,3  = ?

4,3,5  =  (3³  + (4 + 5))  + 1*4  

= ( 27 + 9) + 4

= 40

5,4,3=  (4³  + (5 + 3))  + (1*5 * 4)

= ( 64 + 8) + 20

= 92

 6,2,3  = (2³  + (6 + 3))  + (1*6 * 2* 3)

= (8 + 9) +36

= 53

53 is Correct option

Logic

a , b , c  = d

=> (b³ + (a + c) )   + 1 * a     ( if 1st term of Sequence)

    (b³ + (a + c) )   +   1 * a* b     ( if 2nd term of Sequence)

    (b³ + (a + c) )   + 1 * a* b*c     ( if 3rd term of Sequence)

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