Question

4/3(sec2 59 - cot2 31°) - 2/3 sin 90+3 tan2 56x tan2 34 = x/3

Answer 1

=4/3( sec²59° - tan²(90-31)° ) - 2/3 sin 90° + 3 tan56° × cot(90-34)°
=4/3( sec²59° - tan²59° ) - 2/3×1 + 3×tan 56° × 1/tan56°
=4/3×1 - 2/3×1 +3×1
=4/3 - 2/3 + 3
=(4-2+9)/3
=11/3