Question

4(3p+2) – 5(6p-1) = 2(p-8) give answer with formula​

Answer 1

Answer:

4(3p+2)-5(6p-1)=2(p-8)-6(7p-4)+4p

We move all terms to the left:

4(3p+2)-5(6p-1)-(2(p-8)-6(7p-4)+4p)=0

We multiply parentheses

12p-30p-(2(p-8)-6(7p-4)+4p)+8+5=0

We calculate terms in parentheses: -(2(p-8)-6(7p-4)+4p), so:

2(p-8)-6(7p-4)+4p

We add all the numbers together, and all the variables

4p+2(p-8)-6(7p-4)

We multiply parentheses

4p+2p-42p-16+24

We add all the numbers together, and all the variables

-36p+8

Back to the equation:

-(-36p+8)

We add all the numbers together, and all the variables

-18p-(-36p+8)+13=0

We get rid of parentheses

-18p+36p-8+13=0

We add all the numbers together, and all the variables

18p+5=0

We move all terms containing p to the left, all other terms to the right

18p=-5

p=-5/18

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