Question

(4/3x - y/2)(4/3x+ y/2)​

Answer 1

From the given question the correct answer is:

Given :

(4/3x - y/2)(4/3x+ y/2)​

To find:

simplification of  (4/3x - y/2)(4/3x+ y/2)​

Solution:

we have to simplify the expression  (4/3x - y/2)(4/3x+ y/2)​

we know that,

(a+b)(a-b)=a²- b²

the expression is in the form of (a-b)(a+b)

(4/3x - y/2)(4/3x+ y/2)​

we can write the expression (4/3x+ y/2)​ (4/3x - y/2)

From (a+b)(a-b)=a²- b²

we can write the expression

(4/3x+ y/2)​ (4/3x - y/2)= (4/3x)²-(y/2)²

so, 16/9x²-y²/4

Answer 2

Answer:

According to question  we have to simplify the given  expression.

Given expression: (4/3x - y/2)(4/3x+ y/2)​

as we can see that given expression is in the form of identity

$a^{2} - b^{2} = ( a + b ) (a - b )$

hence we can say that ,  $a = \frac{4}{3x}$  and $b = \frac{y}{2}$

Therefore , on substituting values of a and b in above identity we can rewrite as -

(4/3x - y/2)(4/3x+ y/2)​ = $(\frac{4}{3x}) ^{2} - (\frac{y}{2}) ^{2}$

                                   = $\frac{16}{9x^{2} } - \frac{y^{2} }{4}$

hence on simplification of (4/3x - y/2)(4/3x+ y/2)​ we get   $\frac{16}{9x^{2} } - \frac{y^{2} }{4}$