Question

(4:3x2yz)×(1:3y2zx)×(-6xyz2)

Answer 1

Step-by-step explanation:

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Answer 2

$Given \: \Big( \frac{4}{3} x^{2}yz \Big) \times \Big( \frac{1}{3} y^{2}zx \Big) \times (-6xyz^{2})$

$= \frac{4}{3} \times \frac{1}{3} \times (-6) \times x^{2} \times x \times x \times y \times y^{2} \times y</p><p>\times z \times z \times z^{2}$

$= \frac{-8}{3} x^{4} y^{4} z^{4}$

Therefore.,

$\red{ \Big( \frac{4}{3} x^{2}yz \Big) \times \Big( \frac{1}{3} y^{2}zx \Big) \times (-6xyz^{2})}$

$\green {= \frac{-8}{3} x^{4} y^{4} z^{4}}$

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