Question

4.4 g of CO2 and 2.24 litre of H2 at STP are mixed in a container. The total number of molecules present in the container will be

(1) 6.022 x 1023
(2) 1.2044 x 1023
(3) 2 mole
(4) 6.023 x 1024
​

Answer 1

Answer:

Total number of Molecules in the container = 0.2 x 6.022 x 10^23 = 1.2044 x 10^23.

Answer 2

Answer:

2) 1.2044 × 10^23

Explanation:

Mass of the CO2 present = 4.4 g  (Given)

Litres of H2 = 2.24 litre (Given)

Thus, the molar mass of CO2 = 12 + 2 × 16 =44g  

Number of moles of CO2 -

= Mass/Molar mass

= 4.4/44

= 0.1mol  

Volume of H2 present at STP = 2.24 litre  

Molar volume of H2 at STP = 22.4 litre  

Numbers of moles of H2

= 2.24/22.4

= 0.1 mol  

Total number of moles present in the mixture = 0.1 + 0.1 = 0.2 mol  

Total number  of molecules = 0.2 × 6.022 × 10 ^ 23  

= 1.2044 × 10^23

Thus, the total number of molecules present in the container will be  1.2044 × 10^23.