4.4 gram of an oxide of nitrogen gives 2324 L of nitrogen and 60g of other oxide of nitrogen gives 22.4L of nitrogen at Stp
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Explanation:
Correct option is
B
multiple proportions
For the first oxide, the ratio of the mass of the oxide to the volume of the nitrogen liberated is
2.24
4.4
=1.96
For the second oxide, the ratio of the mass of the oxide to the volume of the nitrogen liberated is
22.4
60
=2.67
These two are in the ratio
2.67
1.96
=
1.33
1
=
4
3
or 3:4
Hence, this illustrates the Law of multiple proportions.
Note: In the above example, we have used volume of nitrogen which is proportional to the mass of nitrogen.
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