Question

(4/5)^2 X (4/5)^5 = 2k+1

solve k.

Answer 1

Answer:

helo guys its your answer

(1)

Step-by-step explanation:

even no roots is decided ... The given equation x2 – 2(5 + 2k)x + 3(7 + 10k) = 0 is in the form of ax2 + bx + ... 4(5 + 2k)2 – 12(7 + 10k) = 0. (2)Answers and Solutions

(m, n) = (2, 1) gives the triple (3, 4, 5), while (m, n) = (5,2) gives the ... (1), then so also does (x, y) = ((2k + 1)u + 2k(k + 1)v, 2u + (2k + l)v).