Question

(4/5)^x *(4/5)^7=(4/5)^2x-1 find the value of x PLZ answer

Answer 1

Answer:

$( \frac{4}{5} ) ^{x} \times ( \frac{4}{5} ) ^{7} = ( \frac{4}{5} ) ^{2x - 1} \\ \\ ( \frac{4}{5} ) ^{x + 7} = ( \frac{4}{5} ) ^{2x - 1} \\ \\ x + 7 = 2x - 1......its \: \: \: \: a \: \: \: \: method \: \: \: \: \: that \: \: \: \: we \: \: \: \: should \: \: \: \: remove \: \: \: \: the \: \: \: \: base \: \: \: \: of \: \: \: \: the \: \: \: \: equation \\ \\ 7 + 1 = 2x - x \\ \\ 8 = x \\ \\ so \: \: \: \: the \: \: \: \: \: value \: \: \: \: \: of \: \: \: \: \: x \: \: \: \: \: = \: \: \: \: \: \: \: \: \: \: 8$