Math, asked by Mridulp8831, 1 year ago

4/5th of the voters in bellary promised to vote for sonia and the rest promised to vote for sushma. Of these voters, 10% of the voters who had promised to vote for sonia, did not vote on the election day, while 20% of the voters who had promised to vote for sushma did not vote on the election day. What is the total no. Of votes polled if sonia got 216 votes?

Answers

Answered by enyo
47

Answer: Total no. of votes polled is 264.


Step-by-step explanation:

Given that 4/5of the voters in bellary promised to vote for sonia and the rest promised to vote for sushma.

Now, let the voters in bellary promised 4x votes for sonia and x votes for sushma.

The voters who actully voted to sonia= 4x-4x*10%= 4x-0.4x= 3.6x

The number of votes sonia got= 216

So,

3.6x= 216

x= 216/3.6= 60

And

The voters who actully voted to shushma= x-20% of x= x- 0.2x= 0.8x

Now,

Total polled votes= 3.6x +0.8x= 4.4x

So,

Total polled votes= 4.4*60= 264

Answered by abhilash7995
23

Answer:

4/5 of voters means 80%. so Sonia was promised 80% of the votes and Sushma the remaining 20%.

out of the 80% that promised to vote Sonia, only 72% voted because 10% didn't vote. 10% of 80 is 72.

similarly, 20% of the voters didn't vote as promised to Sushma. so she got only 16% votes. which means that only 88% of the people voted in the election.

Now, it's mentioned that Sonia got 216 votes. if 72% of the votes she got, equates to 216, then 88% of the votes equate to what? (unitary method).

(88 * 216)/72 = 88*3 = 264 votes.

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