Question

factorise 8x^2y^3-x^5

Answer 1

Answer :

Now,

$8 {x}^{2} {y}^{3} - {x}^{5} \\ \\ = {x}^{2} (8 {y}^{3} - {x}^{3} ) \\ \\ = {x}^{2} ( {(2y)}^{3} - {x}^{3} ) \\ \\ = {x}^{2} (2y - x)(4 {y}^{2} + 2xy + {x}^{2} )$
which is the required factorization.

#MarkAsBrainliest

Answer 2

Here's Your Answer

question-8x^2y^3-

Answer in the attachment