Question

4/6 to the power -2 +1/4 to the power-3 +2/7 to the power -1

Answer 1

Hey friend,
Here is the answer you were looking for:
${( \frac{4}{6}) }^{ - 2} + {( \frac{1}{4} )}^{ - 3} + {( \frac{2}{7} )}^{ - 1}$

We know that,

${( \frac{a}{b} )}^{ - m} = {( \frac{b}{a} )}^{m}$

$= {( \frac{6}{4} )}^{2} + {( \frac{4}{1} )}^{3} + {( \frac{7}{2} )}^{1} \\ \\ = \frac{ {6}^{2} }{ {4}^{2} } + {4}^{3} + \frac{7}{2} \\ \\ = \frac{36}{16} + 64 + \frac{7}{2} \\ \\ = \frac{36 \times 1 + 64 \times 16 + 7 \times 8}{16} \\ \\ = \frac{36 + 1024 + 56}{16} \\ \\ = \frac{1116}{16}$

In decimal = 69.75


Hope this helps!!

If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.

@Mahak24

Thanks...
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