Math, asked by 31and91, 7 months ago

(4^7)^2×(4^-3)^4 = solve​

Answers

Answered by kathryn55
0

Answer:

answer is 16

Step-by-step explanation:

(4^7)^2 × (4^-3)^4

(4)^14 × (4)^-12 ; when bases are same powers are multiplied

(4)^14-12; when the bases are same powers are added

(4)^2

=16

hope it helps u

Answered by GuptaAayush
0

Answer:

Please mark as brainliest

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