Question

Three forces f1 f2 and f3 are acting on a particle such that the particle remains in equilibrium if f1 is equals to 2 i

Answer 1

your complete question is -> Three forces F1, F2 and F3 are acting on a partcle such that the particle remains in equilibrium. If F1 = (2i +3j)N and F2 = (2j + 2k)N find F3.

solution : F1 , F2 and F3 are acting on a particle such that the particle remains in equilibrium.

so, F1 + F2 + F3 = 0

⇒F3 = -(F1 + F2)

given, F1 = (2i + 3j)N

F2 = (2j + 2k)N

then, F3 = -(F1 + F2)

= -{(2i + 3j) + (2j + 2k)}

= -{2i + 5j + 2k}

hence, F3 = -2i - 5j - 2k

magnitude of force F3 = |F3| = √{(-2)²+(-5)²+(-2)²}

= √{4 + 25 + 4}

= √33 N

≈ 5.74N

hence, force F3 = -2i - 5j - 2k and magnitude of F3 is 5.74N

Answer 2

Explanation:

hope this helps you