Question

4.8 g O2 is mixed with 0.15 moles of iron. Given that iron (II) oxide will react with any available oxygen to form iron (III) oxide completely, the mass of iron (III) oxide formed would be :

Answer 1

Answer:

47.7gram

Explanation:

1. Calculate the no. moles of oxygen molecule= given mass/ molar mass= 4.8÷32= 0.15 moles
2. Total no. of moles in Fe3O2(iron 3 oxide)= moles of oxygen + moles of iron =0.15+0.15=0.3
3. Mass of Fe3O2= no. of moles ×molar mass
4. Molar mass of Fe3O2=159 so
5. Mass of Fe3O2=0.3 ×159=47.7 gram

Answer 2

Answer:

mole of O2 will be 0.15 by mole method

here limiting reagent is Feo whose mole is 0.15

by balancing the equation 2 mole of Feo forms 1mole of Fe2O3 .

therefore moles form by 0.15=0.078

therefore mass of Fe2O3= 159*0.075=12gram