Question

4.90 gram of potassium chlorate when heated produce 1.92 gram of Oxygen and the residue left Behind weight 2.96 gram show that illustrate the law of conservation of mass

Answer 1

Answer:

If 4.9 g of potassium chlorate is used then it gives O2 and KCL.

From the problem statement it is understood that 1.92 g of Oxygen is produced and the residual mass is 2.96g.

Mass of the products come to 1.92+2.96=4.88g.

Since 4.88 g is very close to 4.9 g, therefore it can be deduced that the conservation of mass is valid in this case.

Answer 2

Answer:

mass of reactant = 4.90g

mass of product = mass of o2 + mass of residue

= 1.92 + 2.96

= 4.88

since 4.88 g is very close to 4.90 g, therefore it can be deduced that the conservation of mass is valid in this case............

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