4^a=5,5^b,6^c=7,7^d=8then find a*b*c*d
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Answer:
log4
Step-by-step explanation:
4^a=5
=> a log4=log5
=> a = (log4/log5)
similarly, b=(log6/log5)
c=(log7/log6)
d=(log8/log7)
a*b*c*d= (log8/log4)=(log(4+4)/log4)
=(log4*log4)/log4
=log4
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