Math, asked by akshyap, 1 year ago

4^a=5,5^b,6^c=7,7^d=8then find a*b*c*d​

Answers

Answered by Boundless
1

Answer:

log4

Step-by-step explanation:

4^a=5

=> a log4=log5

=> a = (log4/log5)

similarly, b=(log6/log5)

c=(log7/log6)

d=(log8/log7)

a*b*c*d= (log8/log4)=(log(4+4)/log4)

=(log4*log4)/log4

=log4

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