4. A 72 kg parachutist has a speed of 92 m/s at an altitude of 1102 m above the ground.
a. Determine the kinetic energy possessed by the parachutist.
b. Determine the potential energy possessed by the parachutist.
C. Determine the total mechanical energy possessed by the parachutist.
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Answer:
KE= 304704Nm PE=777571.2Nm ME=808041.2Nm
Explanation:
KE=1/2m*v^2
=1/2*72*92^2
=36*92^2
=304704
PE=mgh
=72*9.8*1102
=777571.2
ME= KE+PE
=304704+777571.2
=808041.2
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