Question

4(a+b)-6(a+b)^2
What will be the answer of it

Answer 1

Answer:

Step-by-step explanation:a+b=6 ———-equation 1

a-b=4 ———-equation 2

adding both the equations,

a+b+a-b=6+4

2a=10

a=5//

Substitute a’s value in equation 1,

5+b=6

b=1//

Hence,

a²+b² = 5² + 1²

=25 + 1

=26

Answer 2

SOLUTION :

Given that,

$4(a + b) - 6 {(a + b)}^{2}$

To solve this problem, remember the identity :

${(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2}$

PROCESS :

$4(a + b) - 6 {(a + b)}^{2}$

$4(a + b) - 6( {a}^{2} + 2ab + {b)}^{2}$

Now multiplying the terms, we get,

$4a + 4b - 6 {a}^{2} - 12ab - 6 {b}^{2}$

$- 6 {a}^{2} - 6 {b}^{2} + 4a + 4b - 12ab$

Hence this is the required answer.