[4(a)-b²/ab -16] [(a)-b²-ab/ab] :a³-b³/ab
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Answer:
Here’s a simple algebraic proof starting with the expansion of (a-b)^3
explanation
(a-b)^3 = a^3–3ab(a-b)-b^3
(a-b)^3+ 3ab(a-b)=a^3 - b^3
(a-b)((a-b)^2+3ab) =a^3-b^3
(a-b)(a^-2ab+b^2+3ab)=a^3-b^3
a^3-b^3=(a-b)(a^2+ab+b^2)
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