Question

4) A bag contains 3 red & 5 black balls. A
ball is drawn at random from the
bag. What is the probability that the ball
drawn is not red?​

Answer 1

Step-by-step explanation:

Here,

Total no. of balls=3+5=8

n(S)=8.

Let A be the event that ball drawn is not red.

Number of which are not red=5.

n(A)=5.

P(A)=n(A)/n(S)=5/8.

Therefore the probability that ball drawn is not red is 5/8.

Answer 2

Answer:

Your answer is:

There are 3 red balls and 5 black balls

therefore,

Sample space={ R1,R2,R3,B1,B2,B3,B4,B5}

n(S)=8

Event A :The ball drawn is not red .

A={B1,B2,B3,B4,B5}

n(A)=5

p(A)=n(A)/n(S)

p(A) =5/8

hope it will help you

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