4.
A balloon filled with N O is pricked with a sharper point and plunged into a tank of CO, unde
pressure and temperature. The balloon will both am 8503
a) Be enlarged
b) Shrink
c) Collapse completely
d) Remain unchanged in size
Answers
Explanation:
The balloon will be enlarged.
Explanation: It can be explained by Graham's Law of effusion.
Graham's Law: This law states that the rates of effusion of gases is inversely proportional to the square roots of their molar masses at the same temperature and pressure.
\frac{Rate_A}{Rate_B}=\sqrt{\frac{MolarMass_B}{MolarMass_A}}
Rate
B
Rate
A
=
MolarMass
A
MolarMass
B
......(1)
where,
Rate_ARate
A
= rate of gas A.
Rate_BRate
B
= Rate of gas B
In the question, it is given that the balloon was filled with methane first and then it was plunged into the tank filled with hydrogen gas, we take the rate of Hydrogen to rate of methane, we get
Gas A = Hydrogen gas
Gas B = Methane gas
Molar mass of Hydrogen gas = 2g/mol
Molar mass of Methane gas = 16g/mol
Putting in the values in equation 1, we get
\frac{Rate(H_2)}{Rate(CH_4)}=\sqrt{\frac{16}{2}}
Rate(CH
4
)
Rate(H
2
)
=
2
16
Rate(H_2)=\frac{4}{\sqrt{2}}\times Rate(CH_4)Rate(H
2
)=
2
4
×Rate(CH
4
)
Rate(H_2)=2.828\times Rate(CH_4)Rate(H
2
)=2.828×Rate(CH
4
)
Hence, the balloon will be enlarged.