Question

4.
A block of mass 1 kg is placed on a rough wedge
which is fixed on an elevator moving upward with
constant velocity 2 m/s. The block m is at rest
w.rit. wedge. Net reaction force on the block is
2 m/s
<
30°
(1) 5 N
(3) 7.5 N
(2) 10 N
(4) 12 N​

Answer 1

Answer:

5N

Explanation:

as the block is placed perpendicularly to the rough wedge therefore

F=mgsin theta

theta = 30 (given)

m = 1 kg also given

then F = 1× 10× 1/2

F= 5N

Answer 2

Answer:

10N

Please refer to the picture attached!

Explanation:

The question can also be directly solved from the diagram. In equilibrium, R = mg.

Hope this helps!