Question

4. A body, initially at rest, starts moving with a constant
acceleration 2 ms-2. Calculate : (i) the velocity
acquired and (ii) the distance travelled in 5 s. 10
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Answer 1

Answer:

Assuming you want the velocity after 5s, it will be 2*5=10m/s

The distance will be 1/2at², as the body was initially at rest

Therefore the distance covered will be 1/2*2*5²

Cancelling 1/2 and 2, we get the distance as 5² which is equal 25m.

hope it will help u

Answer 2

Answer:

Initial velocity, u = 0 m/s

Acceleration, a = 2 m/s^2

( i ). Velocity required, v = u + at

By 1st Law of Newton's motion,

v = 0 + 2 × 5 = 10 m/s

Velocity required = 10 m/s

( ii ). Distance travelled in 5 sec,

s = ut + 1/2 × ( at^2 )

s = 0 + (2 × 25) /2

s = 50/2

s = 25 m.

Distance travelled, s = 25 m.