Question

4. A body of mass 10 kg is moving with a uniform velocity of 100ms. What is the force required to stop
the body in 10 seconds?
A) -100N
B) +95N
C) +100N
D) -105N​

Answer 1

Answer:

+100 N

Explanation:

First first the deceleration of the body required to come to rest using equation of motion v - u = at

since body comes to rest, final velocity = 0.

Therefore,

-u = -a*t

-100 = -a * 10

Hence a = 10m/s²

Now we know F = ma

F= 10 kg * 10 m/s²

F = +100N