Find the acceleration of a car and its displacement from the following observations: Time Speed (in km/h) 3:15 pm 26 3:45 pm 60
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Given:
The speed at different time is 26 and 60 km/hr
To find:
The acceleration of the car and its displacement is
Solution:
The speed in m/sec 26×5/18=7.22
The speed in m/sec 60×5/18=16.66
The time difference 30 min = 30×60=1800 sec
The acceleration = 16.66-7.22/1800
a=0.005 m/sec²
The displacement
s=16.66²-7.22²/2×a
s=22.54 m
So the displacement id 22.54 m
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