Question

4. A box contains 5 red balls and 3 green balls. What is the probability of choosing (a) a red ball? (b) A green ball?​

Answer 1

S = {5 red balls + 4 green balls + 3 blue balls}

N(S) = (12)

Event A = Choosing a Red Ball

A = {5 red balls}

N(A) = (5)

P(A) = n(A)/n(S) = 5/12

Event B = To choose a Blue Ball

B = {3 blue balls}

N(B) = 3

P(B) = n(B)/n(S) = 3/12 = 1/4

Therefore probability of choosing a red ball is 5/12 (42%) , and that of blue balls 1/4 (25%