Physics, asked by raghuyadav674, 2 months ago


4. A force of 10 N acts for 20 second on a body of mass 2 kg initially at rest. Calculate the energy required
by the body and the work done by the applied force.

Answers

Answered by joshua5685
0

Answer:

More than 19.62N

Explanation:

So weight= mass x gravity

Gravity on earth:9.81

9.81x2= 19.62

So we need more than 19.62N to make it move as balanced forces or forces less than 19.62N

Answered by anthonypaulvilly
0

Answer:

F = 10N

mass = 2kg

F = ma

a = F / m = 20 / 2 = 5m/s²

acceleration (a) = 5m/s²

time (t) = 20s

initial velocity (u) = 0

displacement (s) = ut + at²/2

s = 0 + 5×20² / 2

s= 5 × 20 × 20/2

s = 5 × 20 × 10  

s = 1000m

Work done = F × s

                   = 10×1000

                   = 10000j

v = u + at

v = 0 + 5×20

v = 100m/s  

Kinetic energy = 1/2mv²

                        = 1/2 × 2 × 100 × 100

                        = 10000joules

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