Question

4.a). In the right- triangle AABC, ABC=90°, ACB=60°, and AC= 6 cm, Find thelengths of BC and AB. Also find the area of the triangle.b). Rationalize the denominator$14 \div 5 \sqrt{3 - \sqrt{5} }$​

Answer 1

BC=3 cm

AB=3√3 cm

Step-by-step explanation:

given:-

ABC=90°

ACB=60°

AC=6cm

By sin theta= Opposite/hypothenus=AB/AC

sin 60°= √3/2

Then,

√3/2=x/6

then we get,

x=6√3/2

x=3√3

:•AB=3√3

By Pythagoras theorem

(AC)^2=(AB)^2+(BC)^2

(BC)^2=(6)^2+(3√3)^2

BC=√9

BC=3 cm

Hence,

AB=3√3 cm

BC=3 cm

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Hope it helps..