4. A lever of first order has a total length of 3 m and is able to lift a load of 60 N with a force
of 30 N. Find the position of the fulcrum.
shagunsneh1236:
ans is 1 m from 60N and 2 m from 30N but I want the process
Answers
Answered by
6
Explanation:
Given data :
load= 60 N
Effort (force) = 30N
Let ".x " be the distance of fulcrum
from the load
Now
Effort arm= (3-x)
We know that
Load× load arm = Effort × Effort arm
60×= 90-30 x
90x= 90
x = 90/90 =1
Therefore, position of the fulcrum is 1 m from the load .
Answered by
2
Answer:
Explanation:
Given data :
load= 60 N
Effort (force) = 30N
Let ".x " be the distance of fulcrum
from the load
Now
Effort arm= (3-x)
We know that
Load× load arm = Effort × Effort arm
60×= 90-30 x
90x= 90
x = 90/90 =1
Therefore, position of the fulcrum is 1 m from the load
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