Science, asked by harshithaande58900, 6 months ago

4.
A linear object of 10 cm length lies along the axis of a concave mirror of radius of curva
30 cm, the nearer end lying 18 cm from the mirror. The magnification produced is:
A) 5.77
B) 6.77
C) 7.77
D) 8.77​

Answers

Answered by HINABIUCHIHA
0

Answer:

I think a=5.77 ........

Answered by aaditya1234567890
0

Answer:

Magnification produced is -5

Explanation:

u = 18 cm

r = 30 cm

f = r/2 = 15 cm

From relation,

\frac{1}{u} + \frac{1}{v} = \frac{1}{f}

For concave mirror,

u is negative

v is negative

f is negative

Thus,

\frac{1}{-18} + \frac{1}{v} = \frac{1}{-15}

-\frac{1}{18} + \frac{1}{v} = -\frac{1}{15}

\frac{1}{v} = -\frac{1}{15} + \frac{1}{18}

\frac{1}{v} = \frac{-6 + 5}{90}

\frac{1}{v} = \frac{-1}{90}

v = -90 cm

Magnification = -v/u

M = -\frac{(-90)}{-18}

M = - 5

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