4.
A linear object of 10 cm length lies along the axis of a concave mirror of radius of curva
30 cm, the nearer end lying 18 cm from the mirror. The magnification produced is:
A) 5.77
B) 6.77
C) 7.77
D) 8.77
Answers
Answered by
0
Answer:
I think a=5.77 ........
Answered by
0
Answer:
Magnification produced is -5
Explanation:
u = 18 cm
r = 30 cm
f = r/2 = 15 cm
From relation,
For concave mirror,
u is negative
v is negative
f is negative
Thus,
v = -90 cm
Magnification = -v/u
M =
M = - 5
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