Question

4. A man goes 15 m due west and then 8 m due north. How far
is he from the starting point?
(Hint. AC = AB2square + BCsquare) ​

Answer 1

Step-by-step solution:

His distance from the starting point is AC.

AC can be calculated using Pythagoras Theorem.

Applying Pythagoras theorem

(AB)2+(BC)2=(CA)2

(15)2+(8)2=(x)2

225+64=(x)2

x2=289

x=289=17m

Hence the man is 17m from the starting point.

Answer 2

Step-by-step explanation:

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