Question

4. A man have certain number of oranges. He divides them into two lots A and B. He sells the first lot at the rat of Rs 2 for 3 oranges and the second lot at the rate of Rs 1 per orange and gets a total of Rs 400. If he had sold the first lot at the rate of Rs 1 per orange and the second lot at the rate of Rs 4 for 5 oranges, his total collection would have been Rs 460. Find the total number of oranges.

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Answer 1

Let the number of oranges in Lot A be x.

Let the number of oranges in Lot B be y.

Given that he sells the first lot at the rate of 2 for 3 oranges = 2x/3.

Given that he sells the second lot at the rate of 1/- orange and gets a total of 400 = y

= > (2x/3) + y = 400

= > (2x + 3y)/3 = 400

= > 2x + 3y = 1200    ------------ (1)


Given that if he had sold the first lot at the rate of Rs. 1 per orange = > x.

Given that if he had sold the second lot at the rate of 4 for 5 oranges = > 4y/5.

Given that the total collection would be 460.

= > x + (4y/5) = 460

= > 5x + 4y = 2300   --------- (2)


On solving (1) * 4& (2) * 3, we get

8x + 12y = 4800

15x + 12y = 6900

--------------------------

-7x = -2100

x = 300.


Substitute x = 300 in (1), we get

= > 2x + 3y = 1200

= > 2(300) + 3y = 1200

= > 600 + 3y = 1200

= > 3y = 1200 - 600

= > 3y = 600

= > y = 200


Therefore the total number of oranges = 300 + 200

                                                                  = 500.




Hope this helps!

Answer 2

Ur answer is in the pic