4. A man is 3 times as old as his son. After 15 years, he will be only twice as old as his son. Find the
present ages.
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1
Answer:
45 and 15
Step-by-step explanation:
Let man age=x
Son age= y
x=3y..........Eqn 1
x+15 = 2(y+15)
x+15 = 2y + 30
3y +15 = 2y + 30 (Substituting x=3y in this equation)
y= 30=15
y=15
Thus, x=45
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