Question

4. A particle is thrown up vertically with a velocity of 50m/s. What will be its velocity at
the highest point of the journey? How high would the particle rise? What time
would it take to reach the highest point? Take g= 10m/s
PLS ANSSWER THIS IN DETAILED

Answer 1

Answer:

5 second

Explanation:

u=50m/s

g=−10m/s²

The velocity at the highest point will be zero

Thus, v=0

Height can be calculated as,

v²−u² =2gs

0−2500=−20s

s=125m

Time can be calculated as,

v=u+gt

0=50+(−10)t

t=5sec

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Answer 2

Answer:

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Explanation:

u= 50m/s

g= -10m/s^2

The velocity at the highest point will be 0 m/s

Thus v=0

Height can be calculated by

2gs=v^2-u^2

-20s= -2500

s= 125m

Time :

v= u+gt

0=50-10t

-50=-10t

t= 5sec